Answer:
[tex]1.10\cdot 10^{18}N[/tex]
Explanation:
The magnitude of the gravitational force between two objects is given by :
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where :
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
In this problem:
[tex]r=4.20\cdot 10^{10}m[/tex] is the distance between Venus and the Earth
[tex]m_1=4.87\cdot 10^{24} kg[/tex] is Venus mass
[tex]m_2=5.97\cdot 10^{24} kg[/tex] is the Earth's mass
Substituting, we find the gravitational force between the two planets:
[tex]F=(6.67\cdot 10^{-11})\frac{(4.87\cdot 10^{24})(5.97\cdot 10^{24})}{(4.20\cdot 10^{10})^2}=1.10\cdot 10^{18}N[/tex]
