The number of pits in a corroded steel coupon follows a Poisson distribution with a mean of 5 pits per cm2. Let X represent the number of pits in a 1 cm2 area.

NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.

Find P(X = 2).

Respuesta :

Answer:

P(X = 2) = 0.0842

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Mean of 5 pits per cm2

This means that [tex]\mu = 5[/tex]

Find P(X = 2).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 2) = \frac{e^{-5}*5^{2}}{(2)!} = 0.0842[/tex]