A bag contains 43 U.S. quarters and seven Canadian quarters. (The coins are identical in size.) If six quarters are randomly picked from the bag, what is the probability of getting at least one Canadian quarter

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Answer:

0.616

Step-by-step explanation:

The number of Us quarters is 43 while the number of Canadian quarters is 7.

The number of quarters we are to pick is 6

Mathematically, the probability of getting at least one Canadian quarter = 1 - probability of getting no Canadian quarter

This means we have to calculate the probability of getting no Canadian quarter first.

The total number of possible outcomes is 50C6 = 15,890,700

If we are to get all to be US quarters, that means we are getting exactly 6 out of 43 = 43C6 = 6,096,454

Hence, probability of no Canadian quarters is 6,096,454/15,890,700 = 0.384

The probability of at least 1 Canadian quarters is thus 1-0.384 = 0.616