Respuesta :

miljanamilovanovic12

Answer:

x1=2 and x2 =-3/2

Step-by-step explanation:

2x^2-x-6=0 (quvadratic equation)

a=2, b=-1, c=-6

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-1)+sqrt((-1)^2 - 4*2*(-6)))/2*2

x1 =(1+sqrt (1+48))/4

x1= (1+sqrt(49))/4

x1 =(1+7)/4

x1=8/4

x1=2

x2=(-b-sqrt(b^2-4ac))/2a

x2=(1-7)/4

x2=-6/4

x2=-3/2

jlpbossluis

Answer:

X=2

Step-by-step explanation:

Easy, easy!

Let's use trial and error!

Since we can factor this equation, let's do it!

[tex]2x^{2} -x-6=0\\2x^{2} -x=6\\x(2x-1)=6\\\\[/tex]

So this means that we have 2 factors: x and (2x-1)

Those 2 factors multiplied by each must other equal 6.

So at the top of my head two numbers that multiplied by each other equal 6 are 3 and 2.

Let's try x=3 and (2x-1)=2

Since x=3,

[tex](2x-1)=2\\(2(3)-1)=2\\(6-1)=2\\(5)\neq 2[/tex]

It means that we should keep trying!!!

Let's try x=2 and (2x-1)=3

Since x=2,

[tex](2x-1)=3\\(2(2)-1)=3\\(4-1)=3\\3=3[/tex]

So we have our answer!!!

x=2

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