20180090
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A growth medium is inoculated with 1,000 bactena, which grow at a rate of 15% each day What is the per
culture 6 days after inoculation?
y=1000(1 15) 2,313 bactena
y=1000(1 15) 2,660 bacteria
y=1000(15)° 7.594 bacteria
y = 1.000(15). 11,391 bactena
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Respuesta :

calculista

Answer:

[tex]y=1,000(1.15)^x[/tex]

[tex]2,313\ bacteria[/tex]

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

[tex]y=a(1+r)^x[/tex]

where

y is the number of bacteria

a is the initial value

x is the number of days

r is the rate of change

we have

[tex]a=1,000\ bacteria\\r=15\%=15/100=0.15[/tex]

substitute

[tex]y=1,000(1+0.15)^x[/tex]

[tex]y=1,000(1.15)^x[/tex]

For x=6 days

substitute the value of x in the equation

[tex]y=1,000(1.15)^6=2,313\ bacteria[/tex]

rskyler33

Answer:

it is A

Step-by-step explanation:

Population after n days is given by

             P_n=P_0(1+r)^n

Initial population, P₀ = 1000

Increase rate, r = 15 % = 0.15

Number of days, n = 6

Substituting

            P_n=P_0(1+r)^n\\\\P_6=1000(1+0.15)^6\\\\P_6=1000(1.15)^6\\\\P_6=1000\times 2.313\\\\P_6=2313

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