Step-by-step explanation:
Here, f(x) is the given polynomial.
By remainder Theorem,
When divided by (3x-1),
f(1/3) = -3........(1)
When divided by (x+1),
f(-1) = -7.........(2)
Another polynomial is 3x²+2x-1
Solving,
3x²+2x-1
= 3x²+3x-x-1
=3x(x+1)-(x+1)
=(3x-1)(x+1)
So
f(x) = (3x-1)(x+1)Qx + (ax+b)
For f(-1),
-7 = -a+b
b= a-7
For f(1/3),
-3 = a/3+b
or, -3 = a/3+a-7
or, 4×3 = 4a
or a = 3
Also, b = 3-7 =-4
Hence, remainder is (3x-4)
