A 22.4 L vessel contains 0.02 mol H2 gas, 0.02 mol N2 gas, and 0.1 mol NH3 gas. The total pressure is 700 torr. What is the partial pressure of the H2 gas

Respuesta :

Answer:

Partial pressure of [tex]H_{2}[/tex] is 98 torr

Explanation:

Mole fraction (x) of a gas in mixture = (no. of moles of the gas)/(total no. of moles of gases in mixture)

Here, total no. of moles of gases in mixture = (0.02 + 0.02 + 0.1) moles = 0.14 moles

So, mole fraction of [tex]H_{2}[/tex] gas in mixture,  [tex]x_{H_{2}}=[/tex] [tex]\frac{0.02}{0.14}=0.14[/tex]

Let's assume all three gases and their mixture behaves ideally.

Therefore, in accordance with Dalton's law of partial pressure for ideal gases-

                      [tex]P_{H_{2}}=x_{H_{2}}\times P_{total}[/tex]    

Here, [tex]P_{H_{2}}[/tex] and [tex]P_{total}[/tex] are partial pressure of [tex]H_{2}[/tex] and total pressure of mixture respectively.

So, [tex]P_{H_{2}}=(0.14)\times (700torr)=98torr[/tex]