Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 [tex]in^{2}[/tex]
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = [tex]\frac{F}{A}[/tex]
⇒ P = [tex]\frac{6.4}{0.4}[/tex]
⇒ P = 16 [tex]\frac{lb}{in^{2} }[/tex]
This is the pressure inside the cylinder.
Let force applied on the brake pad = [tex]F_{1}[/tex]
Area of the brake pad ([tex]A_{1}[/tex])= 1.7 [tex]in^{2}[/tex]
Thus the pressure on the brake pad ([tex]P_{1}[/tex]) = [tex]\frac{F_{1} }{A_{1} }[/tex]
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P = [tex]P_{1}[/tex]
⇒ 16 = [tex]\frac{F_{1} }{A_{1} }[/tex]
⇒ [tex]F_{1}[/tex] = 16 × [tex]A_{1}[/tex]
Put the value of [tex]A_{1}[/tex] we get
⇒ [tex]F_{1}[/tex] = 16 × 1.7
⇒ [tex]F_{1}[/tex] = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = [tex]\frac{F_{1} }{4}[/tex] = [tex]\frac{27.2}{4}[/tex] = 6.8 lb
⇒ The force applied on one wheel during braking.
