Respuesta :
Answer:
Automated menu
[tex]\bar X= 6.7[/tex]
[tex] s = 3.045[/tex]
[tex] CV = \frac{s}{\bar X}[/tex]
[tex] CV= \frac{3.045}{6.7}= 0.454= 45.4\%[/tex]
Live agent menu
[tex]\bar X= 4.27[/tex]
[tex] s = 1.125[/tex]
[tex] CV = \frac{s}{\bar X}[/tex]
[tex] CV= \frac{1.125}{4.27}= 0.263= 26.3\%[/tex]
So then we can conclude that we have lower variation for the Live agent menu since the coefficient of variation is lower compared to the Automated menu
Step-by-step explanation:
We can solve this by case
Automated menu
Data: 11.7 7.4 3.9 2.9 9.2 6.3 5.5
We can begin calculating the mean with the following formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex]\bar X= 6.7[/tex]
Now we can calculate the standard deviation with the following formula:
[tex]s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] s = 3.045[/tex]
Now we can calculate the coeffcient of variation with this formula:
[tex] CV = \frac{s}{\bar X}[/tex]
And replacing we got:
[tex] CV= \frac{3.045}{6.7}= 0.454= 45.4\%[/tex]
Live agent menu
Data: 6.2 2.9 4.4 4.1 3.4 5.2 3.7
We can begin calculating the mean with the following formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex]\bar X= 4.27[/tex]
Now we can calculate the standard deviation with the following formula:
[tex]s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] s = 1.125[/tex]
Now we can calculate the coeffcient of variation with this formula:
[tex] CV = \frac{s}{\bar X}[/tex]
And replacing we got:
[tex] CV= \frac{1.125}{4.27}= 0.263= 26.3\%[/tex]
So then we can conclude that we have lower variation for the Live agent menu since the coefficient of variation is lower compared to the Automated menu