The correct equation that can be used is [tex](t+4)^{2}=3[/tex] ( Option A)
Step-by-step explanation:
Given Equation:
[tex]4 t^{2}-28 t=6 t^{2}-12 t+26[/tex]
It can be rearranged as follows,
[tex]6 t^{2}-4 t^{2}+28 t-12 t+26=0[/tex]
IT can be simplified as,
[tex]2 t^{2}+16 t+26=0[/tex]
Dividing the above equation by 2, we will get,
[tex]t^{2}+8 t+13=0[/tex]
Now we have to divide the coefficient of t by 2, we will get 4 and squaring 4, and add that value on both sides of the equation we will get,
[tex]t^{2}+8 t+16=-13+16[/tex]
[tex]t^{2}+8 t+16=3[/tex]
