Consider an isolated system, by which we mean a system free of external forces. If the sum of the particle energies in the system increases by 147 joules, what must have been the change deltacapU in the system's potential energy?

Respuesta :

Answer:

The system's potential energy is -147 J.

Explanation:

Given that,

Energy = 147 J

We know that,

System is isolated and it is free from external forces.

So, the work done by the external forces on the system should be equal to zero.

[tex]W=0[/tex]

We need to calculate the system's potential energy

Using thermodynamics first equation

[tex]\Delta U=W-\Delta E[/tex]

Put the value into the formula

[tex]\Delta U=0-147[/tex]

[tex]\Delta U=-147\ J[/tex]

Hence, The system's potential energy is -147 J.

The system's potential energy is -147 J.

Thermodynamics first equation:

Since the sum of the particle energies in the system increases by 147 joules

Since the system should be isolated and free from external force.

Work done by the external force should be equivalent to zero.

So the potential energy should be

= 0- 147

= -147 J

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