The question is incomplete, the complete question is:
Calculate the standard enthalpy change for a reaction? : Fe2O3(s) + 2Al(s) = Al2O3(s) + 2Fe(s).
The standard enthalpies of formation of Fe2O3 and Al2O3 are
-822 and -1669 KJ mol-1 respectively. State whether the reaction is exothermic or
endothermic
Answer:
∆H°reaction= -847KJmol-1
Explanation:
Recall that ∆H°element =0KJ mol-1
Therefore
∆H°reaction = ∆H°products - ∆H°reactants
= (-1669)-(-822)= -847KJmol-1
The reaction is exothermic as ∆H°reaction is negative.
