Answer:
Mass = 12.33 g
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
[tex]\Delta H=m\times C\times \Delta T[/tex]
Where,
[tex]\Delta H[/tex] is the enthalpy change
m is the mass
C is the specific heat capacity
[tex]\Delta T[/tex] is the temperature change
Thus, given that:-
Specific heat = 0.450 J/g°C
[tex]\Delta T=32.5-17.9\ ^0C=14.6\ ^0C[/tex]
[tex]\Delta H[/tex] = 81.0 J
So,
[tex]81.0=m\times 0.450\times 14.6[/tex]
Mass = 12.33 g
The mass of the sample will be "12.33 g".
The energy is transmitted from one object to the next as a consequence of something like a temperature differential.
The heat has been affected by elements such as particle speed, physical properties, as well as particle quantity, among others.
According to the question,
Heat, ΔH = 81.0 J
Specific heat, C = 0.450 J/g°C
Temperature, ΔT = 32.5 - 17.9
= 14.6°C
Enthalpy change of a process be:
→ ΔH = m × C × ΔT
By substituting the values, we get
81.0 = m × 0.450 × 14.6
m = 12.33 g
Thus the above answer is correct.
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