Explanation:
First, we will calculate the total charge as follows.
[tex]q_{total} = \frac{\text{weight of gold to be deposited}}{\text{atomic mass of gold}} \times N_{A} \times \text{charge on electron}[/tex]
= [tex]\frac{0.2 g}{196.97 g/mol} \times 6.02 \times 10^{23} \times 1.6 \times 10^{-19} C[/tex]
= 97.80 C
Now, we will calculate the current required by the jeweler to plate the bracelet as follows.
i = [tex]\frac{q_{total}}{t_{total}}[/tex]
= [tex]\frac{97.80 C}{3 \times 60 \times 60 sec}[/tex]
= [tex]9.05 \times 10^{-3}[/tex] A
or, = 9.05 mA
thus, we can conclude that 9.05 mA current should he use to electroplate the bracelet in three hours.
