The area of the walk is 440[tex]ft^{2}[/tex].
Step-by-step explanation:
We have , a rectangular yard measures 42 ft By 72 ft Is murdered and surrounded by a fence inside a walk that is 4 feet wide goes All the way along the fence. That means we have a rectangle with dimensions of 42 ft by 72 ft and another rectangle that is concentric with dimensions less than 4 ft by previous rectangle i.e. (42-4) ft by (72-4) ft , which is 38 ft by 68 ft.
Now, we know that area of rectangle = [tex]length (breadth)[/tex]
Area of bigger rectangle = [tex]length (breadth)[/tex]
⇒[tex]Area1 = 42(72) ft^{2}[/tex]
⇒[tex]Area1 = 3024ft^{2}[/tex]
Similarly, Area of enclosed rectangle = [tex]length (breadth)[/tex]
⇒[tex]Area2 = 38(68)ft^{2}[/tex]
⇒[tex]Area2 = 2584ft^{2}[/tex]
Now, the area of walk = [tex]Area1-Area2[/tex]
⇒ area of walk = [tex](3024-2584)ft^{2}[/tex]
⇒ area of walk = [tex]440ft^{2}[/tex]
∴ The area of the walk is 440[tex]ft^{2}[/tex].
