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A powerful motorcycle can produce an acceleraDon of 3.50 m/s2 while traveling at 90.0 km/h. At that speed, the forces resisDng moDon, including fricDon and air resistance, total 400 N. (Air resistance is analogous to air fricDon. It always opposes the moDon of an object.)
What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleraDon if the mass of the motorcycle with rider is 245 kg?

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Answer:

1257.5 N

Explanation:

f = Friction force = 400 N

F = Force on the motorcycle

m = Mass of the motorcycle with rider = 245 kg

a = Acceleration = 3.5 m/s²

The net force is given by

[tex]F_n=F-f\\\Rightarrow ma=F-f\\\Rightarrow F=ma+f\\\Rightarrow F=245\times 3.5+400\\\Rightarrow F=1257.5\ N[/tex]

The magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration is 1257.5 N

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