Answer:
If the magnitude of the force is 124
Explanation:
F= 124
T= 62N
Mg a= 200 N Mg b= 100N
[tex]a_{1}[/tex]= 0 [tex]a_{2}[/tex]=0
[tex]/a_{sys}/[/tex]=[tex]\frac{EF}{Mtot}[/tex]
= [tex]\frac{+(20kg) (9.8M/s^{2} )- (10Kg)(9.8M/s^{2} )}{30kg}[/tex]
= 3.2[tex]M/s^{2}[/tex]