The expression that represents the sum of the length and width of the rectangle is [tex]\bold{3a^{-2}}[/tex]
Step-by-step explanation:
Given:
Perimeter of the rectangle = [tex]6a^{-2}[/tex]
To Find:
The sum of the length and width of the rectangle = ?
Solution:
We know that the perimeter of the rectangle is
= [tex](2 \times length) + (2\times width)[/tex]
=[tex]2 (length+ width)[/tex]
From the given that we know
[tex]2 (length+ width) = 6a^{-2}[/tex]
The sum of the length and width is
[tex](length+ width) = \frac{6a^{-2}}{2}[/tex]
[tex](length+ width) =3a^{-2}[/tex]
