A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. 5 seconds later the fish is swimming in the same direction at a speed of 2.5 m/s, the fish's acceleration - 0.4 m/s squared.
Given:
time t = 5.0 s
Inititial velocity - 0.5 m/s
Final velocity = 2.5 m/s
accelaeration a= ?
Solution:
- Acceleration is the rate of change of the velocity of an object with respect to time.
- Accelerations are vector quantities.
- Acceleration can be calculated by:
[tex]\frac{Final\ velocity - Initial\ velocity}{time}[/tex]
Placing the given values:
=> [tex]\frac{2.5\ m/s - 0.5\ m/s}{ 5.0 s}[/tex]
=> = 0.4 m/s squared
Thus, A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. 5 seconds later the fish is swimming in the same direction at a speed of 2.5 m/s, the fish's acceleration - 0.4 m/s squared.
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