Answer:
The stiffness of one of the individual spring is 390 N/m.
Explanation:
It is given that 43 identical springs are placed side-by-side and connected to a large massive block.
The stiffness of the 43 spring combination is 16770 N/m
We need to find the stiffness of one of the individual springs. Let k is the stiffness of one spring. The effective spring stiffness of this width spring is given by :
[tex]K=N\times k[/tex]
[tex]k=\dfrac{K}{N}[/tex]
[tex]k=\dfrac{16770\ N/m}{43}[/tex]
k = 390 N/m
So, the stiffness of one of the individual spring is 390 N/m. Hence, this is the required solution.
