A hypothetical AX type of ceramic material is known to have a density of 3.55 g/cm3 and a unit cell of cubic symmetry with a cell edge length of 0.39 nm. The atomic weights of the A and X elements are 90.5 and 37.3 g/mol, respectively. On the basis of this information, which one of the following crystal structures is possible for this material?a) fluoriteb) zinc blendc) cesium chloride

Respuesta :

Explanation:

For AX type ceramic material, the number of formula per unit cells is as follows.

         [tex]\rho = \frac{n'(A_{c} + A_{A})}{V_{C}N_{A}}[/tex]

or,     [tex]n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}[/tex]

where,   n' = no. of formula units per cell

           [tex]A_{c}[/tex] = molecular weight of cation = 90.5 g/mol

           [tex]A_{a}[/tex] = molecular weight of anion = 37.3 g/mol

          [tex]V_{c}[/tex] = volume of cubic cell = 3.55 [tex]g/cm^{3}[/tex]

           a = edge length of unit cell = [tex]3.9 \times 10^{-8} cm[/tex]

        [tex]N_{A}[/tex] = Avogadro's number = [tex]6.023 \times 10^{23}[/tex]

          [tex]\rho[/tex] = density = 3.55 [tex]g/cm^{3}[/tex]

Now, putting the given values into the above formula as follows.

           [tex]n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}[/tex]

                      = [tex]\frac{3.55 g/cm^{3} \times (3.9 \times 10^{-8})^{3} \times 6.023 \times 10^{23}}{(90.5 + 37.3)}[/tex]

                     = 0.9

                    = 1 (approx)

Therefore, we can conclude that out of the given options crystal structure of cesium chloride is possible for this material.