Respuesta :
This is an incomplete question, here is a complete question.
For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂)
Perform the following calculations:
A) Calculate ΔS at 298 K (ΔH= -220 kJ/mol and ΔG= -206 kJ/mol
B) Assuming that ΔS and ΔH change little with temperature, calculate ΔG at 450 K.
Answer :
(a) The value of ΔS at 298 K is, -0.0469 kJ/mol.K
(b) The value of ΔG at 450 K is, -199 kJ/mol
Explanation :
(a) According to Gibb's equation:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
[tex]\Delta G[/tex] = Gibbs free energy = -206 kJ/mol
[tex]\Delta H[/tex] = enthalpy change = -220 kJ/mol
[tex]\Delta S[/tex] = entropy change = ?
T = temperature in Kelvin = 298 K
Now put all the given values in the above formula, we get:
[tex]-206kJ/mol=-220kJ/mol-298K\times \Delta S[/tex]
[tex]\Delta S=-0.0469kJ/mol.K[/tex]
Thus, the value of ΔS at 298 K is, -0.0469 kJ/mol.K
(b) According to Gibb's equation:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
[tex]\Delta G[/tex] = Gibbs free energy = ?
[tex]\Delta H[/tex] = enthalpy change = -220 kJ/mol
[tex]\Delta S[/tex] = entropy change = -0.0469 kJ/mol.K
T = temperature in Kelvin = 450 K
Now put all the given values in the above formula, we get:
[tex]\Delta G=-220kJ/mol-450K\times -0.0469 kJ/mol.K[/tex]
[tex]\Delta G=-198.895kJ/mol\approx -199kJ/mol[/tex]
Thus, the value of ΔG at 450 K is, -199 kJ/mol
