Answer:
Explanation:
The relation between momentum "P" and impulse "I " is given by the impulse momentum theorem given below,
i.e. impulse is equal to change in momentum.
I= ∆P= P₂ - P₁
F∆t=mv₂ - mv₁
here m is the mass of skateboarder= m= 53.6 kg
initial velocity v₁ = 4.45m/s
final velocity v₂ = 0
now impulse is
I =0 - 53.6 x 4.45 = -235.52 kgm/s
here the final momentum is zero as the final velocity is zero and the initial momentum P₁= mv₁ = 235.52kgm/s
now the strong force that is applied for 1.82 seconds can be calculated as
F= - I / t
F = - 235.52/ 1.82 = - 131 N
in second step the weak force that is applied for 5.34 s can be calculated as
F = - I / t = - 235.52 / 5.34 = - 44.6 N
the negative sign of impulse and applied force indicates that the force is opposite to the direction of motion of the skateboarder.
The magnitude of impulse is -235.52 kg-m/s and the average force on the skateboard are - 131 N and - 44 N respectively, where negative sign indicates that the force is opposite to the direction of motion of the skateboarder.
Given data:
The initial speed of skateboarder is, v₁ = 4.45 m/s.
The time taken to stop by strong force is, t = 1.82 s.
The time taken to stop by weak force is, t' = 5.34 s.
The combined mass of skateboard and skateboarder is, m = 53.6 kg.
In this problem, we need to find the magnitude of average force on the skateboarder at each stop. And to explain the concept behind considering the magnitude of force times.
The relation between momentum (P) and impulse (I) is given by the impulse momentum theorem as,
I = ∆P
I = P₂ - P₁
F∆t =mv₂ - mv₁
here m is the mass of skateboarder. and final velocity of skateboarder.
v₂ = 0
Now calculating the impulse as,
I =0 - 53.6 x 4.45 = -235.52 kg-m/s
here the final momentum is zero as the final velocity is zero and the initial momentum P₁= mv₁ = 235.52kgm/s
Now the strong force that is applied for 1.82 seconds can be calculated as
F= - I / t
F = - 235.52/ 1.82 = - 131 N
And the weak force that is applied for 5.34 s can be calculated as
F' = - I / t = - 235.52 / 5.34 = - 44.6 N
The negative sign of impulse and applied force indicates that the force is opposite to the direction of motion of the skateboarder.
Thus, we can conclude that the magnitude of impulse is -235.52 kg-m/s and the average force on the skateboard are - 131 N and - 44 N respectively, where negative sign indicates that the force is opposite to the direction of motion of the skateboarder.
Learn more about the impulse-momentum theorem here:
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