If Bob and Judy combine their savings of ​$1 comma 700 and ​$700​, ​respectively, and deposit this amount into an account that pays 3 % annual​ interest, compounded​ monthly, what will the account balance be after 12 ​years?

Respuesta :

Answer:

$3,438.45

Explanation:

The amount invested is the sum of Bob's and Judy's savings:

[tex]P=\$1,700+\$700\\P=\$2,400[/tex]

The equation that gives the future value of an investment P, at an annual interest rate r for t years, compounded monthly, is:

[tex]FV = P*(1+\frac{r}{12})^{12t}[/tex]

Therefore, the account balance after 12 years of an initial investment of $2,400 at 3% is:

[tex]FV = \$2,400*(1+\frac{0.03}{12})^{12*12}\\ FV= \$3,438.45[/tex]

The account balance after 12 ​years will be $3,438.45.