Answer:
[tex]W=1837.5J[/tex]
Explanation:
A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:
[tex]W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d[/tex]
In this case, we have:
[tex]F=mg\\h=dcos\theta[/tex]
So, replacing this:
[tex]W=mgh\\W=75kg*9.8\frac{m}{s^2}*2.5m\\W=1837.5J[/tex]
