Answer:
m = 2 ft/s
Explanation:
given,
depth of the scuba diver after 10 s, h₁ = 30 ft
depth of the scuba diver after 45 s, h₂ = 100 ft
average rate of change of the scuba diver = ?
difference of the height
Δh = h₂ - h₁
Δh = 100 - 30
Δh = 70 ft
difference of the time interval
Δt = t₂ - t₁
Δt = 45 - 10
Δt = 35 s
rate of change of the scuba diver
[tex]m = \dfrac{\Delta h}{\Delta t}[/tex]
[tex]m = \dfrac{70}{32}[/tex]
m = 2 ft/s
average rate of change of the scuba diver is equal to 2 ft/s
