Answer:
[tex]159ft/sec[/tex]
Step-by-step explanation:
The average velocity of an object is calculated as the change in the distance over change in the time specified i.e
[tex]V_{avg}=\frac{change in distance }{change in time }[/tex]
Hence we calculate the height at 4secs and at 4.5secs
at 4secs,
[tex]s(t)=16t^{2}+23t+1\\t=4\\s(4)=(16*4^{2})+(23*4)+1\\s(4)=349ft[/tex]
we also calculate the height at 4.5secs
[tex]s(t)=16t^{2}+23t+1\\t=4.5\\s(4.5)=(16*4.5^{2})+(23*4.5)+1\\s(4.5)=428.5ft[/tex]
Hence the average distance is
[tex]V_{avg}=\frac{s(4)-s(4.5)}{4-4.5}\\ V_{avg}=\frac{349-428.5}{-0.5}\\ V_{avg}=159ft/sec[/tex]
