Use her results to estimate the probability that there are more than 5 left-handed students in a class of 30students.
Give your answer as either a fraction or a decimal​

Respuesta :

Answer:

5/30

Step-by-step explanation:

put the smaller number first and then the second number

The probability that there are more than 5 left-handed students in a class of 30 students is 0.1049

How to determine the probability?

The given parameters are:

  • Sample size, n = 30
  • Probability of success, p = 0.11
  • x > 5

To determine the required probability, we make use of the following complement rule:

P(x > 5) = 1 - P(x ≤ 5)

Using a binomial calculator, we have:

P(x ≤ 5) = 0.89508640002

Substitute P(x ≤ 5) = 0.89508640002 in P(x > 5) = 1 - P(x ≤ 5)

P(x > 5) = 1 - 0.89508640002

Evaluate the difference

P(x > 5) = 0.10491359998

Approximate

P(x > 5) = 0.1049

Hence, the probability that there are more than 5 left-handed students in a class of 30 students is 0.1049

Read more about binomial probability at:

https://brainly.com/question/15246027