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You are given 250. mL of a stock 0.100 M Alanine solution and instructed to dilute a portion of it. So, you use a pipette and transfer 5.00 mL of the original stock solution into a flask and add 95.0 mL of water. Select all of the following statements that are correct concerning this procedure. Select all that apply.

A. The concentration in the 5.00 mL portion in the pipette is 0.100 M Alanine

B. The concentration of Alanine in the final diluted solution is 0.100 mole.

C. The amount of Alanine in the diluted solution is the same as the amount of Alanine in the pipette.

D. The amount of Alanine in the original stock solution is the same as the amount in the final diluted solution.

E. The amount of Alanine in the final solution is more than in the original stock solution because you added water.

F. The concentration in the final 100 mL is less than 0.100 M Alanine

Respuesta :

Answer:

C. The amount of Alanine in the diluted solution is the same as the amount of Alanine in the pipette.

D. The amount of Alanine in the original stock solution is the same as the amount in the final diluted solution.

Explanation:

Molar concentration (also called molarity) is defined as a measure of the concentration of a species that is, of a particular solute in a solution, per unit volume of solution.

Given:

Concentration of Alanine = 0.1 M

Initial volume = 250 ml

Molar concentration = number of moles/volume

Number of moles =

1000 ml contains 0.1 M

250 ml contains 250 * 0.1 M/1000 ml

= 0.25 * 0.1

= 0.025 mol

Now we put

0.025 moles of the alanine into 100ml.

= (0.025 * 1000 ml/l )/100 ml

= 0. 25 M of alanine.

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