Answer:
Explanation:
Given
Charge on first cork [tex]q_1=5\ mu C[/tex]
Placed at [tex]r=0.13\ m[/tex] from another cork
Charge on second cork [tex]q_2=-3.2\ \mu C[/tex]
As two charges are opposite in nature therefore they will experience an attractive force
[tex]F_{12}=\frac{kq_1q_2}{r^2}[/tex]
[tex]F_{12}=\frac{8.987\times 10^9\times 5\times 3.2\times 10^{-12}}{(0.13)^2}[/tex]
[tex]F_{12}=\frac{143.8\times 10^{-3}}{1.69\times 10^{-2}}[/tex]
[tex]F_{12}=8.508\ N[/tex]
