Respuesta :
Answer:
[tex]a = 5.13~{\rm m/s^2}[/tex]
Explanation:
According to Newton's Second Law, the acceleration of the sphere is equal to the net force on the sphere divided by its mass, a = F/m.
The net force is the sum of the weight of the sphere and the electrostatic force applied by the lower sphere.
Since both spheres have the same charge, they repel each other, which means that the electrostatic force on the upper sphere is directed upwards. Naturally, the weight of the sphere is directed downwards. So, the net force is
[tex]F_{net} = mg - \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}\\F_{net} = (0.11 \times 10^{-3})(9.8) - \frac{1}{4\pi (8.8\times 10^{-12})}\frac{(25\times 10^{-9})^2}{(10 \times 10^{-2})^2}\\F_{net} = 5.12 \times 10^{-4}~N[/tex]
Therefore, the magnitude of the initial acceleration of the sphere is
[tex]a = \frac{F_{net}}{m} = \frac{5.65\times 10^{-4}}{0.11 \times 10^{-3}} = 5.13~{\rm m/s^2}[/tex]
