Answer:
The new freezing point is 0.98°C
Explanation:
T = m × Kf
m (molality of the aqueous solution) = number of moles of MgCl2/mass of water in kilogram
Number of moles of MgCl2 = 1.7/95 = 0.018 mol
Mass of water = 34.12 g = 34.12/1000 = 0.03412 kg
m = 0.018/0.03412 = 0.528 mol/kg
Kf = 1.86°C/m
T = 0.528 × 1.86 = 0.98°C
The new freezing point is 0.98°C
The lowering of the freezing point of solvents upon the addition of solutes. It is given by:
T = m × Kf
Where,
m (molality of the aqueous solution) = number of moles of MgCl₂ /mass of water in kilogram
Number of moles of MgCl₂ = 1.7/95 = 0.018 mol
Mass of water = 34.12 g = 34.12/1000 = 0.03412 kg
m = 0.018/0.03412 = 0.528 mol/kg
Kf = 1.86°C/m
T = 0.528 × 1.86 = 0.98°C
Thus, the value for new freezing point will be 0.98°C.
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