Answer:
The correct answer is 180,424 g/mol
Explanation:
The expression for osmotic pressure (π) is the following:
π= i x M x R x T
Where M is the molarity of the solution, R is the gas constant and T is the temperature.
i= 1 because the catalase is a nonelectrolyte.
M= m/(VxMW) because the molarity is in mol/L and mol is obtained by the mass (m) divided into the molecular weight (MW)
We introduce this expression in the expression for osmotic pressure and we obtain:
π= [tex]\frac{m R T }{V MW}[/tex]
T= 20ºc= 293 K
V= 14 mL= 0.014 L
So, we directly calculate the molecular weight as follows:
MW= [tex]\frac{m R T}{V \pi }[/tex]
MW= (0.166 g)(0.082 LatmK⁻¹mol)(293 K) (760Torr atm⁻¹)/(0.014 L)(1.2 Torr)
MW= 180,424 g/mol
For an enzyme: 180,424 g/mol= 180.4 kDa (because 1 g/mol= 1 Da)
