Answer:
The correct option is (B) $365,530.
Explanation:
In this problem we need to determine the future value, i.e. the amount at the retirement age.
The formula to commute the future value is:
[tex]\\ FV=A[\frac{(1+r)^{n}-1}{r}][/tex]
Here,
A = annual investment = $5,000
r = interest rate = 8%
n = number of periods = 25
The future value is:
[tex]\\ FV=A[\frac{(1+r)^{n}-1}{r}]\\=5000\times[\frac{(1+0.08)^{25}-1}{0.08}]\\=365529.699\\\approx365530[/tex]
Thus, the amount of money the engineer will have in the account at retirement is $365,530.