Respuesta :
Answer:
Traffic flow = 1125 veh/hr
Average speed = 35.15 mi/hr
Traffic density = 32 veh/mi
Explanation:
Given Data:
average headway= h =3.2 sec
average spacing = s = 165 ft
Required:
Traffic flow, average speed and density of traffic
Solution:
a. Traffic flow
It cn be calculated through relation
[tex]q=1/h[/tex]
[tex]q=1/3.2=0.3125 veh/sec\\q=0.3125*60*60veh/hr\\q=1125veh/hr[/tex]
b. Average Traffic Speed
It can be calculated by the equation
[tex]v=s/h\\v=165/3.2\\v=51.56ft/sec\\v=51.56*3600/5280\\v=35.15mi/hr[/tex]
c. Traffic Density
It can be calculated by
[tex]K=q/u\\K=1125/35.15\\K=32 veh/mi[/tex]
Following are the calculation to the given points:
Given:
average headway [tex](h) =3.2\ sec[/tex]
average spacing[tex](s) = 165 \ ft[/tex]
To find:
Traffic flow=?
average speed=?
The density of traffic=?
Solution:
Traffic flow [tex](q)= \frac{1}{\text{average headway}}=\frac{1}{3.2} = 0.3215\ \frac{veh}{sec}= 1125\ \frac{veh}{hour}[/tex]
Density of traffic[tex]= \frac{1}{\text{average spacing}}= \frac{1}{165}= 0.006\ \frac{veh}{ft}= 32 \ \frac{veh}{mile}[/tex]
Average speed[tex]= \frac{\text{Traffic flow}}{\text{density of traffic}}= \frac{1125}{32} \ = 35\ mph[/tex]
Learn more:
brainly.com/question/14774965
