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An incandescent light bulb can be regarded as a resistor. If its power output is 100W, calculate the resistance of the light bulb and the current drawn by the light bulb, assuming the voltage of the power source is 110V.

Respuesta :

Answer:[tex]121\ \Omega [/tex]

[tex]0.909\ A[/tex]

Explanation:

Given

Power [tex]P=100\ W[/tex]

Voltage applied [tex]V=110\ V[/tex]

Resistance of the bulb is given by

[tex]P=\frac{V^2}{R}[/tex]

[tex]100=\frac{110^2}{R}[/tex]

[tex]R=\frac{12100}{100}[/tex]

[tex]R=121\ \Omega [/tex]

Current drawn by the Power source is given by

[tex]P=V\cdot I[/tex]

[tex]I=\frac{P}{V}[/tex]

[tex]I=\frac{100}{110}[/tex]

[tex]I=0.909\ A[/tex]

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