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Suppose that there is a 1 in 60 chance of injury on a single skydiving attempt. A friend claims there is a 100% chance of injury if a skydiver jumps 60 times. Assume that the results of repeated jumps are mutually independent. (a) What is the probability that 60 jumps will be completed without an injury

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Answer:

Since the results are mutually exclusive then we compute the probability as:

Pr(1) =1/60 or = 0.167

Step-by-step explanation:

Pr(1) is given as the probability of one injury after 60 trails.

Probability is given by : the required outcome/the total number of possible outcome

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