Answer:
59.76 grams of Li₂O
Explanation:
To solve this problem we will first calculate the moles of Li₂O. One mole of given substance always contains 6.022 × 10²³ particles which can be atoms, ions, molecules or formula units. This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 1.204 × 10²⁴ Particles ÷ 6.022 × 10²³
Number of Moles = 2.0 Moles
Secondly, we will convert calculated moles to mass using following relationship.
Moles = Mass / M.Mass
Or,
Mass = Moles × M.Mass
Putting values,
Mass = 2.0 mol × 29.88 g/mol
Mass = 59.76 grams of Li₂O
