The equation d = 3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

The table gives the different distances in meters that Edgar swam with respect to time in seconds.
Time (seconds) Distance (meters)
20 64
40 128
60 192

Assume that Liam and Edgar both swim at a constant rate.

What is the rate of change for each swimmer in terms of meters per second? Who swims faster?

Be sure to label your answers with the name of the swimmer.

Respuesta :

frika

Answer:

Liam's rate = 3 meters per second

Edgar's rate = 3.2 meters per second

Edgar swims faster

Step-by-step explanation:

Liam:

The equation [tex]d=3t[/tex] gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

When [tex]t=0,\ d=0.[/tex]

When [tex]t=1,\ d=3.[/tex]

Rate of change:

[tex]\dfrac{3-0}{1-0}=3[/tex]

Liam's rate is 3 metres per second.

Edgar:

When [tex]t=20, \ d=64.[/tex]

When [tex]t=40,\ t=128.[/tex]

Rate of change:

[tex]\dfrac{128-64}{40-20}=\dfrac{64}{20}=3.2[/tex]

Edgar's rate is 3.2 metres per second.

Edgar swims faster.

Answer:

Liam's rate = 3 meters per second

Edgar's rate = 3.2 meters per second

Edgar swims faster

Step-by-step explanation: