Answer:
313.5 L of Br2 contains 8.428x10^24 atoms
Explanation:
Imol of Br2 occupies 22.4L
Therefore Xmol of Br2 will occupy 313.5L i.e
Xmol of Br2 = 313.5/22.4 = 14moles
1mole of Br2 contains 6.02x10^23 atoms.
Therefore 14moles of Br2 will contain = 14x6.02x10^23 = 8.428x10^24 atoms
Therefore 313.5 L of Br2 contains 8.428x10^24 atoms
