contestada

A U-tube manometer is used to measure the pressure at the stagnation point of a model in a wind tunnel. One side of the manometer goes to an orifice at the stagnation point; the other side is open to the atmosphere (fig. below). If there is a difference of 3 cm in the mercury levels in the two tubes, what is the pressure difference in N/m2 .

Respuesta :

Answer:

[tex]\Delta p=4000.4199\ Pa[/tex]

Explanation:

Given:

  • difference in the column of mercury of u-tube manometer, [tex]\Delta h=3\ cm=0.03\ m[/tex]

We know that the pressure due to height if a liquid column is given as:

[tex]p=\rho.g.h[/tex]

where:

p = pressure

h = height of the liquid

[tex]\rho=[/tex] density of the liquid

  • We have the density of mercury as, [tex]\rho=13593\ kg.m^{-3}[/tex]

Now the difference of pressure in the two tubes of the manometer:

[tex]\Delta p=\rho.g.\Delta h[/tex]

[tex]\Delta p=13593\times9.81\times0.03[/tex]

[tex]\Delta p=4000.4199\ Pa[/tex]

Otras preguntas