Answer:
The final temperature of the iron is 95.86 °C
Explanation:
To solve the question we must first find out the specific heat of iron which is 0.450 J/g°C
Then we list out the known variables
Initialtemperature = 38 °C
Applied heat = 2213 joules
Mass of sample = 85 g
Therefore, the required formula relating the final temperature of the iron to the known variables is
ΔH = m·C·Δθ where ΔH = applied heat, m = mass, C = specific heat capacity
plugging in the values we have
2213 J = 85 g×0.450 J/g° C× (T₂ - 38 °C), where T₂ = The final temperature of the iron
2213 J - 1453.5 J = 38.25 × T₂ or T₂ = 95.86 °C
The final temperature of the iron is 95.86 °C
