The perimeter of a rectangle sandpit is 40 meters. The length of the sandpit is 1 meter less than twice it's width. What are the dimensions of this sandpit

Respuesta :

Answer:

L = 15, W = 8

Step-by-step explanation:

Perimeter = 2(L + W)

P = 40

L = 2W - 1

40 = 2((2W-1) + W)

40 = 4W - 2 + 2W

40 = 6W - 2

42 = 6W

W = 8

Since L = 2W - 1

L = 2(8) - 1

L = 15