Respuesta :
Answer:
[tex]v_{f}[/tex]=12.579m/s
Explanation:
with constant acceleration the displacement is calculated as follows
Δx=([tex]v_{0}[/tex]+[tex]v_{f}[/tex])t/2
for the first 4.10s the [tex]v_{f}[/tex] is the top speed so, and, for the other 5.9s, the speed is constant with value [tex]v_{f}[/tex], so:
100 m =[tex]v_{f}[/tex]*(10-4.1s)+ (0+[tex]v_{f}[/tex])4.1s/2
so [tex]v_{f}[/tex]=100/(5.9+2.05)=12.579m/s
Answer:
12.579m/s:with constant acceleration the displacement is calculated as follows Δx=(+)t/2for the first 4.10s the is the top speed so, and, for the other 5.9s, the speed is constant with value , so:100 m =*(10-4.1s)+ (0+)4.1s/2so =100/(5.9+2.05)=12.579m/s
Explanation: