What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divided into six equilateral triangles.)

What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm Hint A regular hexagon can be divided into six equilateral triangles class=

Respuesta :

Answer:

Exact area = [tex]\frac{3}{2}\sqrt{3}[/tex] square cm

Approximate area = 2.598 square cm

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

[tex]A = \frac{\sqrt{3}}{4}*s^2[/tex]

[tex]A = \frac{\sqrt{3}}{4}*1^2[/tex]

[tex]A = \frac{\sqrt{3}}{4}[/tex]

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

[tex]6*A = 6*\frac{\sqrt{3}}{4}[/tex]

[tex]6A = \frac{3\sqrt{3}}{2}[/tex]

[tex]6A \approx 2.598[/tex]

Ver imagen jimthompson5910