Answer:
Explanation:
Given
Free fall acceleration on mars [tex]g_{m}=3.7\ m/s^2[/tex]
Time Period of pendulum on earth [tex]T=1\ s[/tex]
Time period of Pendulum is given by
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
for earth
[tex]1=2\pi\cdot \sqrt{\frac{L}{9.8}}[/tex]
[tex]L=\frac{9.8}{(2\pi )^2}[/tex]
[tex]L=0.498\ m[/tex]
(b)For same time period on mars length is given by
[tex]L'=\frac{g_m}{(2\pi )^2}[/tex]
[tex]L'=\frac{3.7}{39.48}[/tex]
[tex]L'=0.0936\ m[/tex]
[tex]L'=9.36\ cm[/tex]
