Answer:
Explanation:
Given
Height of boy [tex]h(EF)=6\ ft[/tex]
Distance of boy from mirror [tex]FC=8\ ft[/tex]
Distance of house is [tex]BC=16\ ft[/tex]
We know angle of incident and angle of reflection is same therefore
[tex]\angle FEC=\angle CAB[/tex]
thus [tex]\tan \theta =\frac{FC}{EF}---1[/tex]
Also [tex]\tan \theta =\frac{BC}{AB}----2[/tex]
From 1 and 2 we got
[tex]\frac{FC}{EF}=\frac{BC}{AB}[/tex]
[tex]AB=\frac{16\times 6}{8}[/tex]
[tex]AB=12\ m[/tex]
