Answer:
3,003 different menus can be made showing 5 main courses from 15 choices
Step-by-step explanation:
we need to find how many different menus can be made showing 5 main courses from 15 choices
Total of 15 choices
5 to be selected from 15 choice
'r' is selected from n choices in nCr ways
[tex]nCr= \frac{n!}{r!(n-r)!}[/tex]
Here 5 is selected from 15 in 15C5 ways
[tex]15C5= \frac{15!}{5!(15-5)!}\\15C5= \frac{15!}{5!(10)!}=3003[/tex]
So 3,003 different menus can be made showing 5 main courses from 15 choices
