A curve passes through the point (0,2) and has the property that the slope of the curve at every point PP is five times the yy-coordinate of PP. What is the equation of the curve?

Respuesta :

Answer:

[tex]y=2e^{5x}[/tex]

Step-by-step explanation:

The slope of a curve is given by its derivative function. From the question, its value at any point (x, y) is 5 times y.

[tex]\dfrac{dy}{dx}=5y[/tex]

[tex]\dfrac{dy}{y}=5dx[/tex]

Integrate both sides

[tex]\int\dfrac{dy}{y}=5dx[/tex]

Don't forget the constant of integration

[tex]\ln y= 5x + C[/tex]

[tex]y=e^{5x+C}=e^{5x}\cdot e^C[/tex]

Since C is a constant, then [tex]e^C[/tex] is constant. Let's call it A.

[tex]y=Ae^{5x}[/tex]

At the point (0, 2), when x = 0, y = 2.

[tex]2=Ae^{5\times0}[/tex]

[tex]2=Ae^{0}[/tex]

[tex]A=2[/tex]

Hence,

[tex]y=2e^{5x}[/tex]