Answer: 1.22x10^20 molecules
Explanation:
N2 + 3H2 —> 2NH3
Molar Mass of H2 = 2g/mol
Mass conc of H2 = 6.09×10^−4
n = Mass conc / molar Mass
n = 6.09×10^−4 / 2 = 3.045x10^-4mol
From the equation,
3 moles of H2 produced 2moles of NH3.
Therefore, 3.045x10^-4mol of H2 will be produce = (3.045x10^-4x2) /3
= 2.03x10^-4mol of NH3
1mole of NH3 contains 6.02x10^23 molecules.
Therefore, 2.03x10^-4mol of NH3 will contain = (6.02x10^23x2.03x10^-4) = 1.22x10^20 molecules
Answer:
Molecules NH3 = 1.21*10^20 molecules
Explanation:
Step 1: Data given
Mass of H2 = 6.09 *10^-4 grams
Molar mass of H2 = 2.02 g/mol
Step 2: The balanced equation
N2 + 3H2 → 2NH3
Step 3: Calculate moles H2
Moles H2 = mass H2 / molar mass H2
Moles H2 = 6.09 *10^-4 grams / 2.02 g/mol
Moles H2 = 3.01*10^-4 moles
Step 4: Calculate moles NH3
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
For 3.01 *10^-4 moles H2 we'll have 2/3 * 3.01*10^-4 =2.01*10^-4 moles
Step 5: Calculate molecules NH3
Molecules NH3 = 2.01*10^-4 moles * 6.022 *10^23
Molecules NH3 = 1.21*10^20molecules
